What is the pH of a buffer prepared by adding 6.0 mol of acetic acid and...
What is the pH of a buffer prepared by adding 6.0 mol of acetic acid and 1 mol of NaOH to water to make a 1.0-L solution? Ka for acetic acid is 1.75*10-5 and its pKa is 4.76.
Homework Answers
pH= pka + log [acetate ]/[acetic acid]
acetic acid moles = 6
NaOOH moles added = 1
acetic acid reacts with NaOH to form sodium acetate
henceacetic acid after reaction = 6-1 = 5 ,
acetate moles = NaoH moels reacted = 1
Now [acetic acdi] = moles/vol = 5/1 = 5 , [acetate] = 1/1 = 1 ,
now pH = 4.76 + log ( 1/5)
= 4.06
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