![If I have the reaction HF (aq) + H20 (1) = H3O+ (aq) + F (aq), the expression K = (Select] / [Select]](http://img.homeworklib.com/questions/cb2c59e0-fee7-11eb-8c8c-9faa55fbcb64.png?x-oss-process=image/resize,w_560)
![(Select] [H20] * [F-] [HF] * [F-] [H3O+]*[F] [HE] [HF] * [H20]](http://img.homeworklib.com/questions/cb8422e0-fee7-11eb-b899-5f16fce34273.png?x-oss-process=image/resize,w_560)
![[Select] [HE] [HF] * [H20] [H20] [F-) [H3O+] * [HF]](http://img.homeworklib.com/questions/cbd8d730-fee7-11eb-b669-f9fb51af7676.png?x-oss-process=image/resize,w_560)
Homework Answers
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator)
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator)
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
estion 10 of 65 > Consider the reaction. HF(aq) + KOH(aq) — KF(aq) + H20(1) What...
estion 10 of 65 > Consider the reaction. HF(aq) + KOH(aq) — KF(aq) + H20(1) What is the net ionic equation for the chemical reaction? HF(aq) + K+(aq) + OH(aq) — K+(aq) + F (aq) + H2O(1) O HF(aq) + K+(aq) + OH-(aq) — K+(aq) + F (aq) + H+(1) + OH-(1) O HF(aq) + OH-(aq) —> F-(aq) + H2O(1) HF(aq) + K+(aq) F (aq) + H+(1) HF(aq) + K+(aq) K+(aq) + H2O(1) - 11 of 65 > Calculate either...
Write the concentration equilibrium constant expression for this reaction. F (aq)+H,0" (aq)HF (aq)+H20(1) dº do *...
Write the concentration equilibrium constant expression for this reaction. F (aq)+H,0" (aq)HF (aq)+H20(1) dº do * $ ?
Given the following equilibrium reaction: HI (aq) + H20 <- -> I- (aq) + H3O+ (aq)...
Given the following equilibrium reaction: HI (aq) + H20 <- -> I- (aq) + H3O+ (aq) Indicate which of the following statements are true? a. water is not acting as an acid or base b. water is acting as a acid and its conjusgate base is I- c. water is acting as a base and its conjugate is I- d. HI is acting as a acid and its conjugare baseis I- e. HI is acting as a base and its...
Write a balanced base equation for F"(aq) F (aq) + H20(1) =H30+ (aq) + HF (aq)...
Write a balanced base equation for F"(aq) F (aq) + H20(1) =H30+ (aq) + HF (aq) F"(aq) + H20(1) = H20"(aq) + F(aq) F (aq) + H2O(0) = OH"(aq) + HF(aq) F"(aq) + H20(1)=H*(aq) + HOF(aq) Impossible to determine QUESTION 2 Write a balanced base equation for CH3CH2NH2(aq) CH3CH2NH2(aq) + H2O(1) = H30+ (aq) + CH3CH2NH" (aq) CH3CH2NH2(aq) + H2O(1) = OH(aq) + CH3CH2NH3(aq) CH3CH2NH2(aq) + H2O(1) = H20" (aq) + CH3CH2NH2+(aq) CH3CH2NH2(aq) + H2O(1) = NH4+(aq) + CH3CH2OH(aq) Impossible...
13 Question (3 points) Choose the correct equilibrium constant expression for the following reaction 2HF(g) +H,0()...
13 Question (3 points) Choose the correct equilibrium constant expression for the following reaction 2HF(g) +H,0() H20+ (aq) + HF, (aq) c. K= [H,0+][HE] (HF) [H20+][HE] (HF)[ HO] [H3O+][HF3] [HF] [HO] [HF12 D. K IH,+ HFZ. Choose one: OA Ов < 12.-
ben 39. Write the expression for K for the reaction of hydrofluoric acid with water. HF(aq)+...
ben 39. Write the expression for K for the reaction of hydrofluoric acid with water. HF(aq)+ H2O()F (aq)+ H50 (aq) stes boda a. b i boooong or oto bodedao bsde ey to ednbo od is K = hddp lin stondinpo fan Ersd ealoinen b. K = - [H,0"] o cmuloy sdt oab sob eno С. F K [HF] d. K = [HF] [HF] e. K = [FE,0"]
1. The following reactions all have K > 1. 1) C6H5COO-(aq) + HF (aq) --> F-(aq)...
1. The following reactions all have K > 1. 1) C6H5COO-(aq) + HF (aq) --> F-(aq) + C6H5COOH (aq) 2) C6H5COO-(aq) + HC9H7O4(aq) --> C6H5COOH (aq) + C9H7O4-(aq) 3) HF (aq) + C9H7O4-(aq) --> HC9H7O4(aq) + F-(aq) Arrange the substances based on their relative acid strength F- HF C6H5COO- C9H7O4- HC9H7O4 C6H5COOH strongest acid intermediate acid weakest acid not a Bronsted-Lowry acid 2. The following reactions all have K > 1. 1) NO2-(aq) + HF (aq) --> HNO2(aq) + F-(aq)...
1. The following reactions all have K > 1. 1) C9H7O4-(aq) + HF (aq) --> F-(aq)...
1. The following reactions all have K > 1. 1) C9H7O4-(aq) + HF (aq) --> F-(aq) + HC9H7O4(aq) 2) C9H7O4-(aq) + HNO2(aq) --> HC9H7O4(aq) + NO2-(aq) 3) HF (aq) + NO2-(aq) --> HNO2(aq) + F-(aq) Arrange the substances based on their relative base strength. NO2- HC9H7O4 F- HF HNO2 C9H7O4- strongest base intermediate base weakest base not a Bronsted-Lowry base 2.The following reactions all have K > 1. 1) C6H5COO-(aq) + HF (aq) --> C6H5COOH (aq) + F-(aq) 2) C6H5O-(aq)...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator)
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator)
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
estion 10 of 65 > Consider the reaction. HF(aq) + KOH(aq) — KF(aq) + H20(1) What is the net ionic equation for the chemical reaction? HF(aq) + K+(aq) + OH(aq) — K+(aq) + F (aq) + H2O(1) O HF(aq) + K+(aq) + OH-(aq) — K+(aq) + F (aq) + H+(1) + OH-(1) O HF(aq) + OH-(aq) —> F-(aq) + H2O(1) HF(aq) + K+(aq) F (aq) + H+(1) HF(aq) + K+(aq) K+(aq) + H2O(1) - 11 of 65 > Calculate either...
Write the concentration equilibrium constant expression for this reaction. F (aq)+H,0" (aq)HF (aq)+H20(1) dº do * $ ?
Write a balanced base equation for F"(aq) F (aq) + H20(1) =H30+ (aq) + HF (aq) F"(aq) + H20(1) = H20"(aq) + F(aq) F (aq) + H2O(0) = OH"(aq) + HF(aq) F"(aq) + H20(1)=H*(aq) + HOF(aq) Impossible to determine QUESTION 2 Write a balanced base equation for CH3CH2NH2(aq) CH3CH2NH2(aq) + H2O(1) = H30+ (aq) + CH3CH2NH" (aq) CH3CH2NH2(aq) + H2O(1) = OH(aq) + CH3CH2NH3(aq) CH3CH2NH2(aq) + H2O(1) = H20" (aq) + CH3CH2NH2+(aq) CH3CH2NH2(aq) + H2O(1) = NH4+(aq) + CH3CH2OH(aq) Impossible...
13 Question (3 points) Choose the correct equilibrium constant expression for the following reaction 2HF(g) +H,0() H20+ (aq) + HF, (aq) c. K= [H,0+][HE] (HF) [H20+][HE] (HF)[ HO] [H3O+][HF3] [HF] [HO] [HF12 D. K IH,+ HFZ. Choose one: OA Ов < 12.-
ben 39. Write the expression for K for the reaction of hydrofluoric acid with water. HF(aq)+ H2O()F (aq)+ H50 (aq) stes boda a. b i boooong or oto bodedao bsde ey to ednbo od is K = hddp lin stondinpo fan Ersd ealoinen b. K = - [H,0"] o cmuloy sdt oab sob eno С. F K [HF] d. K = [HF] [HF] e. K = [FE,0"]
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