Question

Two long parallel wires are separated by 8.65 cm and carry currents 1.25 A and 3.85 A. Find the magnitude of the magnetic force that acts on a 4.67-m length of either wire. Number

Answer 1

Magnetic force between wires is given by:

F = u0*i1*i2*L/(2*pi*r)

u0 = 4*pi*10^-7

i1= current in wire 1 = 1.25 A

i2= current in wire 2 = 3.85 A

L = length of wire = 4.67 m

r = separation distance between wires = 8.65 cm = 0.0865 m

So Using these values:

F = 4*pi*10^-7*1.25*3.85*4.67/(2*pi*0.0865)

F = 5.20*10^-5 N = magnitude of magnetic force

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