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A science-fair radio uses a homemade capacitor made of two 40 cm × 40 cm sheets...

A science-fair radio uses a homemade capacitor made of two 40 cm × 40 cm sheets of aluminum foil separated by a 0.30- mm -thick sheet of paper. Assume dielectric constant of paper is 3.0.

What is its capacitance?

Express your answer using two significant figures.

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Answer #1

Capacitance is given by the relation:

C = ke0A/d

where k = dielectric constant = 3

e0 = permittivity of free space = 8.854 x 10-12

A = area = (40x40)*10-4m2 = 0.16 m2

d = separation = 0.30mm = 0.3 x 10-3 m

Plugging in the data we get:

C = 1.4 x 10-8 F

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