
13 Consider a solution of the solute CHCls in the solvent CHBrs. If the molality of...
What is the relationship between the moles of solute and the
mass of solute?
Rewrite the molality expression in terms of grams and molecular
weight.
Background:
Properties that depend on the concentration of particles in solution are called colligative properties. The number of particles in a solvent can affect the freezing or boiling point of solvent. To express the effect of concentration on freezing point or boiling point, molality is used in place of molarity. Molality (m) is the number...
In one experiment, a student compares the freezing point (6.5 oC) of a pure solvent to the freezing point (1.1oC) of the solvent with a solute. If the kf of the solvent is 5.12 oC/m, what is the molality of the solvent with solute solution?
Find the freezing point depression of pure lauric acid-unknown solution. Find the molality of the unknown. Info: Kf= 4.40*C/moles solute Freezing point of pure lauric acid- 43.2*C and freezing point of solution- 42 *C Mass of unknown solid (nonelectrolyte)- 0.0612g, mass of lauric acid- 3.9321g
Solute X (molecular substance) was added to a pure solvent and the freezing point depression was measured to be 7.0°C. Separately, the same amount of solute Y (molecular substance) was added to the same amount of pure solvent and the freezing point depression was measured to be 10.5°C. Which solute (X or Y) has the higher molar mass. Explain your rationale. thank you
Hi, I need some help with Chemistry.
Q1:
Q2:
Here is some background for the questions:
Thank you in advance.
You add 0.0336 moles of benzoic acid solute to 16.00 g of an unknown solvent, which lowers the freezing point of the solvent by 8.6 °C. Calculate the freezing point depression constant (Kf) of the unknown solvent. You dissolve 1.00 g sample of an unknown solute is in 8.00 g of lauric acid, which lowers the freezing point by 5.0...
The freezing point of 53.48 g of a pure solvent is measured to be 41.91 ºC. When 2.94 g of an unknown solute (assume the van 't Hoff factor = 1.0000) is added to the solvent the freezing point is measured to be 39.86 ºC. Answer the following questions ( the freezing point depression constant of the pure solvent is 7.33 ºC·kg solvent/mol solute). -What is the molality of the solution?___ m -How many moles of solute are present? ___mol...
The freezing point of 53.37 g of a pure solvent is measured to be 49.20 ºC. When 2.74 g of an unknown solute (assume the van 't Hoff factor = 1.0000) is added to the solvent the freezing point is measured to be 47.05 ºC. Answer the following questions ( the freezing point depression constant of the pure solvent is 7.83 ºC·kg solvent/mol solute). What is the molality of the solution? m How many moles of solute are present? mol...
How do you find the molality of solute in a solution? Given: A. Freezing Point of Cyclohexane 1) Mass of beaker, test tube (g) - 131.344g 2) Freezing point from cooling curve - 6.9°C B. Freezing point of cyclohexane plus solute 1) Mass of beaker, test tube, cyclohexane (g) - 140.589g 2) Mass of cyclohexane (g) - 9.242g 3) Mass of solute (g) - Trial 1 (0.208g) / Trial 2 (0.206g) 4) Freezing point from cooling curve - 2.1°C *Not...
molecular weight
moles of solute
kg owater insolution
molality of solution
change in freezing point
Naci KCI CaCl, Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) 9 9 9 g/mole g/ mole mole mole kal kg m m -31°C 3 °C...
Drop at freezing point: A student performed the colligative properties experiment for which he measured 50.00mL of a solvent and weighed it giving a mass of 75.25g. I determined that the freezing point of the pure solvent was 1.00C. Then he added 0.30g of an unknown solid and determined that the freezing point of solution was -1.00C. The Kf of the pure solvent is 20.2C / m. Use the information presented above to answer the following questions: 1. What is...