Question

Task:

Write functions for each container type.

Prompt the end-user to enter the volume of water for the pool, then produce a report with the number needed of each container.

Given a swimming pool with a specific volume of water tell me how many of each do I need to empty the pool, and if anything remains, how much? Each container has to be filled to it's maximum capacity. For example a 74 gallon pool will fill 2 garbage cans and 1 bucket, with nothing remaining.

Volumes

Garbage can = 32 gallons

Bucket = 5 gallons

Pail = 1 gallon

Quart = .25 gallons

Pint = .125 gallons

Cup = .0625 gallons

Be able to write this in python

Answer 1

Python code:

# Defining findVolume function
def findVolume(volume):
# if volume is greater than or equal to 32 gallons.
if(volume >=32):
n = volume//32
print(int(n),'Garbage can') # display Garbage cans.
st = n*32
volume = volume-st # Remaining volume.
  
# if volume is greater than or equal to 5 gallons.
if(volume >=5):
n = volume//5
print(int(n),'Bucket')
st = n*5
volume = volume -st # Remaining volume.
  
# if volume is greater than or equal to 1 gallons.
if(volume >=1):
n = volume//1
print(int(n),'Pail')
st = n*1
volume = volume-st # Remaining volume.

# if volume is greater than or equal to 0.25 gallons.
if(volume >=0.25):
n = volume//0.25
print(int(n),'Quart')
st = n*0.25
volume = volume-st

# if volume is greater than or equal to 0.125 gallons.
if(volume >=0.125):
n = volume//0.125
print(int(n),'Pint')
st = n*0.125
volume = volume-st # Remaining volume.
  
# if volume is greater than or equal to 0.0625 gallons.
if(volume >=0.0625):
n = volume//0.0625
print(int(n),'Cup')
s = n*0.0625
volume = volume - st # Remaining volume.
  
# display the Remaining volume
print('Remaining volume:',round(volume,3))
  

# __name__
if __name__=="__main__":
  
# Taking the user input and storing it in variables name volume.
volume=float(input('Enter the volume of water for the pool: '))
# display the message
print(volume,'gallon pool will fill: ')
# Calling the findVolume method with 1 parameter.
findVolume(volume)

Python code screenshot:

# Defining findVolume function def findVolume (volume): # if volume is greater than or equal to 32 gallons. if(volume >=32): n = volume//32 print(int(n), 'Garbage can') # display Garbage cans. st = n*32 volume = volume-st # Remaining volume. # if volume is greater than or equal to 5 gallons. if(volume >=5): n = volume//5 print(int(n), 'Bucket') st = n*5 volume = volume -st # Remaining volume. # if volume is greater than or equal to 1 gallons. if(volume >=1): n = volume//1 print(int(n), 'Pail') st = n*1 volume = volume-st # Remaining volume. # if volume is greater than or equal to 0.25 gallons. if(volume >=0.25): n = volume//0.25 print(int(n), 'Quart') st = n*0.25 volume = volume-st

# if volume is greater than or equal to 0.125 gallons. if(volume >=0.125): n = volume//0.125 print(int(n), 'Pint') st = n*0.125 volume = volume-st # Remaining volume. # if volume is greater than or equal to 0.0625 gallons. if (volume >=0.0625): n = volume//0.0625 print(int(n), 'Cup') S = n*0.0625 volume = volume - st # Remaining volume. # display the Remaining volume print('Remaining volume:',round(volume, 3)) # if name _name__ =="_main_": print() # Taking the user input and storing it in variables name volume. volume=float(input('Enter the volume of water for the pool: ')) # display the message print(volume, 'gallon pool will fill: ') # Calling the findVolume method with 1 parameter. findVolume (volume)

OUTPUT:

Enter the volume of water for the pool: 55 55.0 gallon pool will fill: 1 Garbage can 4 Bucket 3 Pail Remaining volume: 0.0