What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and for Cu2+(aq) is +0.34 V. Give your answer using E-notation with ONE decimal place (e.g., 2.1 x 10-2 would be 2.1E-2; and 2.12 x 10-2 would also be 2.1E-2.). Do NOT include spaces, units, punctuation or anything else silly
What is the value of ΔGo in kJ at 25 oC for the reaction between the...
What is the value of ΔG o in kJ at 25 oC for the reaction between the pair: Cu(s) and Cr3+(aq) to give Cr(s) and Cu2+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and for Cu2+(aq) is +0.34 V. For these questions, I keep getting a negative answer. The correct answer to this question is 6.3E2, and I put -6.3E2. Why is it a positive number? Isn't the reaction spontaneous?
Question 1) What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Pb(s) and Sn2+(aq) to give Sn(s) and Pb2+(aq) Use the reduction potential values for Sn2+(aq) of -0.14 V and for Pb2+(aq) of -0.13 V Question 2) What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Cr(s) and Cu2+(aq) to give Cu(s) and Cr3+(aq) Use the reduction potentials for Cr3+(aq) is -0.74 V and...
QUESTION 2 What is the value of the equilibrium constant at 25 °C for the reaction between the pair: Ag(s) and Mn2+(aq) to give Agt(aq) and Mn(s) Use the reduction potential values for Ag+(aq) of +0.80 V and for Mn2+(aq) of -1.18 V Give your answer using E-notation with NO decimal places (e.g., 2 x 10-2 would be 2E-2; and 2.12 x 10-2 would also be 2E-2.). Do NOT include spaces, units, punctuation or anything else silly!
Use the standard reduction potentials from the following table to choose the weakest reducing agent among those shown below. Ag+(aq) + - + Ag(s) E° = 0.80 V Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Ni2+(aq) + 2e + Ni(s) E° = -0.26 V Cr3+(aq) + 3e- → Cr(s) E° = -0.74 V Mn2+(aq) + 2e → Mn(s) E° = -1.19 V О Ni(s) Ag(s) Cr(s) Mn(s) Cu(s)
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Question 33 (3 points) (33) For a galvanic cell notation: (-) Ni /Ni2+ (aq) // Au3+ (aq) / Au (+), The electrode potentials: Eº (Ni2+/ Ni) = -0.257 V, E ° (AU3+ / Au ) = 1.498 V. The cell potential Eºcell (a) 1.241 V (b) - 1.755 V O (0) 1.755 V (d) 1.498 Why Question 35 (3 points) (35) For galvanic cell: (-) Cr/ Cr3+ (aq) / Cu2+ (aq) / Cu(+), the correct half...
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Question 35 (3 points) (35) For galvanic cell: (-) Cr/ Cr3+ (aq) // Cu2+ (aq) / Cu (+), the correct half reactions are 0 (a) Cr3+ (a) Cr3+ + 3e → Crat (-) electrode; Cu+ 2e → Cu2+ at (+) electrode (b) Cr - 3e → Cr3+ at (-) electrode; Cu2+ + 2e → 2 Cu at (+) electrode Occ) cr (c) Cr + 3e → Cr3+ at (-) electrode; Cu2+ - 2e → Cu...
I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
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An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
Given the following list of half-reaction reduction potentials, identify the reaction that will occur spontaneously as written: Half-reaction E° (V) -0.74 Cr3+ (aq) + 3 e ---> Cr (s) Sn4+ (aq) + 2 e ---> Sn2+ (aq) +0.154 -0.440 Fe2+ (aq) + 2 e ---> Fe(s) Fe3+ (aq) + e ---> Fe2+ (aq) +0.771 2 Cr (s) + 3 Fe2+ (aq) ---> 3 Fe (s) + 2 Cr3+ (aq) 2 Cr3+ (aq) + 3 Sn2+ (aq) ---> 3 Sn4+ (aq)...
When determining the relative reduction potentials of several electrode systems, why does it not matter what is chosen as a reference electrode? What action(s) is/are required to compare electrode potentials measured relative to different references? A galvanic cell is created according to the following cell notation: Al(s) | Al3+(1.0M) || Cu2+(1.0M) | Cu(s) Reduction Half Reaction E ̊ (volts) Al3+(aq) + 3e- -> Al(s) -1.66 Cu2+(aq) + 2e- -> Cu(s) 0.34 What is the overall cell potential? What would be...
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V