Question

13. A 40-gram (40g) steel pellet moving at 40 hits and embeds 10cm into a 600g block of war. Assuming the wax offers a constant resisting force to the pellet until the pellet reaches the 10cm inside the wax, what is the ratio of the initial kinetic energy of the system (before collision) to the final kinetic energy of the system (after collision), 40m 40g (B) 1% 600g (A) 32 (c) % (DX

answer is B (16/1) need work/explanation

Answer 1

40g 40m/s | Good INT Ims/ mass of steel pellet = 40g Speed of steelpellet: 40m/s Mass of waxen Block - Goog Initial Momentum = msxvs = 40gx4 m/s final momentus = (mazan B = (600g) x VB from CONSERVATION OF MOMENTUM Ms X Vs =(MB X VB & 40x40 = (600+40) XVB & VB = 40xh8 to s - 34 2 640 VB=5 m/s Now Before collision Rez 4 msx V5 + O (Blockat rest) After colles in Kef = 1 (Ms +MB) x V8 Ratio of Initi I KE and final KE 8 8 kei = 4 x 40gx 40x40 = 40 x 40 x 40 x 2x2 = 16 KEF 1x 140t6oo) x 52 x/2 644x4x$ ī /x(40+600) x 56x52

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