Question

Which best describes the dipole-dipole attractions? They are specifically the interaction between: Select the correct answer below: O two formal, or permanent, dipoles an instantaneous dipole and a formal dipole O two temporary dipoles O none of the above

Answer 1

Which best describes the dipole - dipole otractions? They are specifically the interaction between Ang it (as two formal or bermanent diboles 032) In order to know the total pressure of gas collected over water, we need to know: Ang. water vapour and (c) both breasure A and B of bure ie, both bressure of the gas at Since, the concentration of solution to be prepared = 25 mg/ml . In 1me of solution to be prepared amount of MgCl₂ = 25 mg I . In 1.5l of solution to be prepared amount of Molly required = 25x1.50 SO 900.0 2.0 = 25 mg x 1500 me = 37500mg of Mglla Now, the given concerderation of stock solution of MgCl2 = 120mg ( me * 120mg of My C, is present in stock Boletion of volume = ame Moche is bresent in stock solution of volume = sme 120 mg out in stock is present in stock Mol solution solution of volume = 37500 mg of of values 1 mdx 37500mg 120mg 000 1 12312. Some of 20 = stock solution Thes, 312.50 ml of stock solution are required to prepare 1.5e of 25 mg/me solution.

reaction is :-) The given balanced chemical Pb(NO3)₂ (aq) + K ₂ SO 4 (og PbSO4 + 2 KNO3(02) Given concentration of Pb(NO₃), solution = 0.15M ON Therefore, in Il of Pb(NO3)₂ solution, no of moles of Pb(NO3) present = 0.15 moles u. In 0.50 l of Pb(NO3), solution, no. of moles of Pb(NO3), bresent= (0.15x0.50) moles ef Pb(702) The = 0.075 moles of Pb(NO3h from the given balonced chemical reaction, we know that to 1 mole of Kosez solution is required to completely percipitate the Pb2+ in a mole of Pb(NO3). Thus, 0.075 moles of K₂SO4 is required to completely bercipitate the Pf 2t in 0.075 moles of Pb (AVO) .. Given concentration of K₂SO4 solution = 0.20M : 0-20 moles of K2SO4 is present in solution of volume = 1 l u 1 mole of K₂SO4 is present in solution of volume=1 l 0²20 2. 0.075 moles of K₂SO4 is present in solution of volume = 1 x 0.075 e 0.20 = 0.375 litres of 0.20M K ₂ SO 4 solution. Thus, 0.375 litres of 0.20 M K₂SO4 solution will completely percipitate the P62+ in 0.50 litre of 0.15M Pb (NO) solution.