Question

1. A 0.012 kg bullet is fired horizontally into a 0.1 kg wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant k= 150 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 0.8 meter and comes to complete stop, what was the speed of the bullet at impact with the block? -www-

Answer 1

Using conservation of energy as the bullet moves toward the mass wooden block it has only kinetic energy . When it is embedded into wooden block and compresses it ,it will have potential energy so these two energies must be conserve .

71 22 -kr 2 2

So

kr2 V m

V 150 x 0.82 0.012

So we get

v=89.442719099991 m/s