
Describe how to obtain the graph of g(x)= -4f(x+2)-3 from the graph of f(x).
Explain how the graph of f can be obtain from the graph y=1/x .f(x)=(-1/x-2)-2the graph can be obtain from y=1/x by reflecting across the x-axis , and shifting it how?
Letf be a function and let g(x) = f(x + 2) – 3. Describe how to draw the graph of g using the graph off. Shift the graph off right 2 units and up 3 units Shift the graph off left 2 units and up 3 units Shift the graph off left 2 units and down 3 units Page 14 of 35 Shift the graph off right 2 units and down 3 units
Graph the function. Use the graph of f(x) = 5* to obtain the graph of g(x) = 5 **.
4) Let f(x) = 2*-2 + 1 a) Graph f(x). Describe the transformations that you make to 24 to obtain the graph of f(x) b) f(x) has an inverse, f'(x). Find f-'(x) c) Graph f-'(x).
5) Suppose you have the graph of the function f(x). To obtain the graph of the function g(x) = 2 + f(x-3), you must do what to the graph of f(x)? a) Shift up 3 units b) Shift right 2 units c) Shift up 3 units and left 2 units d) Shift up 2 units and right 3 units e) Shift up 2 units and left 3 units f) Shift down 2 units and left 3 units
Question 8 Graph the function. Use the graph of f(x) = 4 * to obtain the graph of g(x) = 4 *-1 -2
1/2 POINTS SCALC8 2.5.062. 5 + 4f(x), where f(3) = 5 and f(3) = 3, find h'(3). If h(x) = h'(3) =
Question 8 Give an appropriate answer. [ 4f(x) – 5g(x) Let lim f(x) = -3 and lim g(x) = 4. Find lim x-10 X-10 X-10 -S + g(x) 8 -2 10 7
Describe the graph of the function g by transformations of the base function f. (0,2 (-2, 0) ,0) (0, -4) 1 g(x) = f(x – 4) - 2 g(x) = f(x + 4) + 2 g(x) = f(x - 4) + 2 g(x) = f(x + 4) - 2
Find the slope of the line tangent to f(x) at x = 3. The graph of f(x) is shown below. Move the point on the curve to x = 3. Then plot two points on the tangent line. Finally, calculate the slope of the tangent line at x = 3. Answer 2 Points Keypad Points can be moved by dragging or using the arrow keys. Any lines or curves will be drawn once all required points are plotted and will...