Question

 

 

 
Answer the following three questions (a, b, and c) based on the radioactive decay curve of iridium-192, shown below. Click on the graph and move the mouse over a point to get values for that point.
 
If the initial sample is 5.25 g. what mass of the original iridium-192 remains after 130 days?
Estimate the half-life of the radioisotope.
How many days would it take for two-thirds of the sample to decay?
 
You must understand the graph to answer this question. The x axis represents the time in days, and the y axis shows the sample remaining after x days. For example, about 63% of the sample remains after 50 days.
Consider the percent of the original sample that remains after 130 days.
The half-life is the amount of time that it takes for one-half of the radioactive material to decay.
Think about the amount of sample left after two-thirds of the material decays.
0 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1

(a) From the graph, the percentage of the sample after 130 days is \(30 \%\)

The mass of the initial sample is \(5.25 \mathrm{~g}\).

So, calculate the mass of original iridium-192 after 130 days as follows:

mass of original \(=30 \% \times\) mass of the initial sample

$$ \begin{aligned} &=\frac{30}{100} \times(5.25 \mathrm{~g}) \\ &=1.575 \mathrm{~g} \\ &\cong 1.58 \mathrm{~g} \end{aligned} $$

(b) From the graph, the half-life at \(50 \%\) sample is about 75 days.

(c) Two-third of the sample decay means one-third remains, that is \(33 \%\). Then time is 120 days from graph.

Add a comment
Know the answer?
Add Answer to:
    Iridium-192 is one radioisotope used in brachytherapy, in which a radioactive source is placed...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT