Homework Answers
145.98 = 10010001.01100010
Then there are 232-16 = 216 addresses possible. The range of addresses is from 145.98.0.1 to 145.98.255.255
If there are 2 subnets, 1 bit will be used for the subnet. So each subnet will have 232-17 = 215 addresses.
For subnet 1 range of IP shall be 145.98.0.1 to 145.98.127.255
For subnet 2, the range of IP shall be 145.98.128.1 to 145.98.255.255
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