Question

Problem 3 10 Ohms a) Compute i and Va b) Compute the power 10V dissipated across each resistor Problem 4 5 Ohms Va 15 Ohms a) Compute i and Va 10 Ohms b) Compute the power supplied by the voltage source

Answer 1

V_a is the voltage across 10 ohm resistance which is obtained from voltage divider rule Therefore V_a = V times 10 ohm/10 ohm + 5 ohm = 10 times 10/15 = 100/15 = 6.66 v From ohm's law, V = I R_eff therefore from circuit R_eff = 5 ohm + 10 ohm V = 10 v Therefore 10 = 1 (15 ohm) I = 10/15 I = 0.66 A Power dissipated by 5 ohm is i^2 R = (0.66)^2 5 ohm P_5 ohm = 2.2 W Power dissipated by 10 ohm is i^2 R = (0.66)^2 10 ohm \r\n V_a = Voltage across 10 ohm resistor = voltage across 15 ohm also V_a = v times 10 ohm 10 ohm/5 + 10 ohm = 10 times 10/15 = 100/15 = 6.66 v From ohm's law, v = I R_eff R_eff = 5 + (151110) = 15 + 15 times 10/25 = 15 + 6 = 21 ohm Therefore 10 =