I've tried this a million
times and I keep getting it wrong!
Kp = Kc* (RT) ^(delta n )
delta n= 2-4 = -2
so,
Kc = Kp* (RT)^2
Kc= ( 4.46)* ( (273+197)*8.314)^2
Kc = 68100549
I've tried this a million times and I keep getting it wrong! The equilibrium constant for...
The equilibrium constant for the chemical equation N2(g)+3H2(g)−⇀↽−2NH3(g) is Kp=0.111 at 231 ∘C. Calculate the value of Kc for the reaction at 231 ∘C.
The equilibrium constant (Kp) for the chemical equation N2(g)+3H2(g)−⇀↽−2NH3(g) is 0.0200 bar−2 at 273 °C. Calculate the value of the Kc for the reaction at 273 °C.
The equilibrium constant for the chemical equation N,(g) + 3H2(8) - 2NH3(g) is Kp = 0.0881 at 225 °C. Calculate the value of K, for the reaction at 225°C. Kc =
I've tried calculating the mL and mols after balancing the
equation but I keep getting it wrong. please help
Write the balanced chemical equation for the following acid and base reaction. (Use the lowest possible whole number coefficients. Include states-of-matter under the given conditions in your answer.) H2S04(3q) + Na0H(aq) chemPad Help Greek 2SO4(aq) + 2NaOH(aq) -2H20(/) + Na2SO4(aq) Correct. Using the balanced reaction above, calculate the amount of 0.0024 M NaOH that would neutralize 22 mL of 0.0025 M...
The equilibrium constant for the chemical equation N2(g) 3 H2(g)2NH3 (g) is Kp = 0.0146 at 183 oC. Calculate the value of Kc for the reaction at 183 °C.
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. A) For the reaction 3A(g)+3B(g)⇌C(g) Kc =...
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)?n where R=0.08206 L?atm/(K?mol), T is the absolute temperature, and ?n is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)?2NH3(g) for which ?n=2?(1+3)=?2. Part A For the reaction 3A(g)+3B(g)?C(g) Kc...
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. For the reaction 2A(g)+2B(g)⇌C(g) Kc = 80.2...
1. The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. Part A For the reaction 3A(g)+2B(g)⇌C(g)...
I keep getting this problem
wrong help please
At a certain temperature, the equilibrium constant for the following chemical reaction is 0.00176. At equilibrium, the concentration of AB is 1.325 M, the concentration of BC is 2.425 M, and the concentration of AC is 0.140 M. Calculate the concentration of B at equilibrium. AB(aq) + BC(aq) 근 AC(aq) + 2B(aq) Number .635