Question

Use the graph provided to complete the table. f(0) y = f(0) 0

Answer 1

use the form a cor (bx-C) td (0,2), From the graph the points are (271,-4), (411,2). y = 3 cos (2) - 1 The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined Interval Notation : (-0,oo). Find the magnitude of the trig term 3 cos (2)-1 by taking the absolute value of the coefficient. 3. The lower bound of the range for cosine is bound by substituting the negative magnitude of the coefficient into the equation y= -3-1 y=-4

The upper bound of the range for cosine is found by substituting the positive magnitude of the coefficient into the equation.. y=3-1 y=2. . . The range is - is usys 2 Domain: (-0,00), {X/XER} Range : [-4,2] {41 42 42 2} * Asymtote: cosine functions do not have asymphotes..... .: x Appro nimate Zero: Set 3 cou ()-120 3 cos ()-1 cos (1) = ģ en cor (1) x = 2x (05" () X= 2.46191883

the The first cosine and function fourth is poritive in quadrants, - 217 – 2.46191883 x = 10.10445177 The period of the cos ( 2 ) function Ň 47 so values will repeat every 4t radians in both directions : = 2.461918+3+4Tn, 10.10445777 +4TH for any integer n. The maximum and minimum cannot be this i not r not a a quadratic this because determined function * Amplitude lal=3 21 - UT * period 2T bl 7. y. 360(%)-!). az 3, b= ²,c=0, d=-1