Question

Exercise 3.3.13 Fjand F2 are equal and opposite, both of magnitude 800 N. a. Determine the sum M + M, for the moments created at Aby the two forces Fjand F2, acting on the structure shown. Call this sum M3. b. What is the scalar component of My about the axis of the shaft AB? Assume a = 195 mm, b = 220 mm, c = 270 mm. 100 mm 100 mm 100 mm F2 a. M3 - i+ If+ IkNm b. MAB - Nim

Answer 1

a fi 450 9 D usto. co-ordinates ژ c ز Now A (0,0,0); D (a+0, 6,0) (a,0,6) A(0,0,0); D(465, 220, o se c195,0,220) (465-0) + C220 - 0) + ( 6-0) 465 F +220 ġ toĥ AC 2 195 f + oủ + 220K (or AD = z } 2

Now Both A & A acts on yon plane, by f g h with z-axis = 900 made Angle A with as graxes у 45 / 21 wolt n 180-450 1350 with y -450 .. V2 fi with magnitude; Now is rector form, f fi ( cas 1850 + cos(46) } + cas 902 800 ( + te jook) 565.685 (-; tj to ķ (-$+j+oß) Moment at a due to ABX 2 F mi=MA fi * 565.685 220 0 465 -1 1 0 565. 685 fil J-j (0) (465 +220) Nam = 565.685 (0.6857) N Ñ. 387. ugyk. Nm in similare Fashion ?- 2 for f

y fq -450 90 - 450t 135 with an wethaf fo 3135084 Cas90 (- tor 800 ( ta 2 fog (Cos (~450); + los 135 taſ to 565.685 (Å -h +0%) moment about a due to fa; AC x F2 & 2 565.685 M2 2 M AZ 220 195 o - -1 K Nimm, + 220 565.685 z M3 - M, + M2 565,685 [ ; (920)-5(-220) -195 As a (-2002 1209. 195 Ela4.45 i +104.45-10.2ošķJNm 387.494 Ñ + [-124.451+1246401 (124.45 ? + 124.45 ] + 297. 186 moment about AB NA (unit vector of Art lateta i + oj tok) 110.308K Å AB TABI Cate+a)? CN 2

MAB 13 - 13 - (27 vs 1 + 129 ฯๆ 15:27 i 233 . 186 86 K 6). C.. -- 189 - 95 Nm