Question

1) For the following balanced reaction: 3H2(g) + 1 N2(g) → 2 NH3(g) a) Calculate the heat of reaction (AHRXN) using AH from Table 1 b) calculate the heat of reaction (AHRXN) using Bond Energies from Table 2 c) Is the reaction endothermic or exothermic? Explain based upon your results from part a and b. 2) Calculate the energy required in Joules to heat 275.5 g of ice at -40.0°C to water at 60.0°C. 3) For blue light with an energy of 454 nm: a) calculate the frequency in Hz. b) calculate the energy in kJ/mole for a mole of photons

Answer 1

(9) =-46.11 Hylmy Samen ( 3H2(g) + 1 N2c9) 3:2 NA Athina, o Dhan= {4! (Produce, -ED, HoReacters) oft Neco) = 0 244 HCM ] - [307 terbunt thing] =(26-46:11))-C 3 Custo) Dhana - 92.22 Kylmall 3th + N2 → 2NH₂ bond ce band calculate than using Bond energies HH = 436 k Ilona N-H ³ 389 Kyl mare NEN S 946 (my Here in NHA 3 N-H bond so, enery is 3x436 946 2x1167 1167 kylmy for NH3 is than = E Ana Veneto state Agent O Haan[3Dsoned aru) + Dhond 'twan) ] - [2 Above "entry] Dhon = [36436) + 946)-[2 x(167)] = (1306+946) -(2334) To Horn = -50 kJ/mol "Recictons Padu ( this recietion is exothermie.bcz.in both (a&(6) OHan is -ve.it indicate that heut rend release from reaction, cs Scanned with CamScanner

275,5 amice at -40 C to water at 60°c . Mole of the Wt specifichent Jlgic MWE Water = 4.18 = Cw - 275.5 íce = 2.09=cp 18 Steam = 2.00 Tmote = 15-30mriel Heat of fussion water- 334.6519 (Lice) -40°C Qs OC Qzone 23_, 60' water pato 1. BT = 60c ice Tadlocke q=m. GiAT . 275.52.09 X40 Tq 2 23031.8) 22=m. Lice qzim.co.ot = 27575x half X 60 - 2275-5X 334-4 (93 = 690950W 122=921272) now, Roten 9, +92 +93 23031.8t 92127.2 7 6 9095.4 [ane = 18425404 ] Scanned with CamScanner

Q-3 blue light a = 454 nm =454x10 m c=3 x 10 mis - v (frequency) s (trequency) - 1 = 3x108 1 4548109 = 6.607 xloxio 109 Te = 6.60 x 109H2) 23 (b) energy in kylmre for more photone h = 6.626 X 10 34 JS E=Nahe O NA2 Avogado number = 6.02 x 100% purtiere Es 6.022 x10x61626X1834 of 454 x 109 E = 0.2635X10S may E= 263.5 x 1033 / moy TE=2635 kJ/mar/ Scanned with CamScanner