Question

Quru! Select all that apply. 10x2 +10y2 + 3x4 + 6x?y2 + 3y4 Consider the function f(x,y) = x² + y² Your answer: The surface of f(x,y) is described by the paroboloid z = 10 + 3(x? +y?). The surface of f(x,y) intersects the xz-plane in the parabola z = 10 + 3x²,x70 The domain of the function f(x,y) is the set R2 -{(0,0)). The surface of f(x,y) is described by the paroboloid z = 10 +3(x² + y²),z * 10. ofxx,y) + f (x,y) = 6(x + y) for (x,y) *(0,0).

Answer 1

fex,y) 102e toge + Bachat " + 6x y² + 3y4 xat you f(x, y) 10 (x+4y) + 3 (x2+433 x² + y² if x40 and yto fcsony) : 10+ 3(x++y") So, fex, y) 3 pasabocoed t= 10 + 3 (se?tye), (2,4) (90) ie Z #10 Domain of fex,y)= RP-{[0,0]} xz plane : y=0) old Intersection with Z= 10t 8x² xto fe cxY): 62 fey (2,8) = 64. be cx,y) + fyrking)= 6(x+y) 2 (3.4) 40,0) So, all statements Quo true except statement (i).