Question

Calculate the solubility at 25°C of PbCrO4 in pure water and in a 0.0060M Na2CrO4 solution.

Ksp of PbCrO4 is 2.8×10⁻¹³

Round both of your answers to 2 significant digits.

solubility in pure water: g/L solubility in 0.0060 M Na2CrO4 solution: g/L

Answer 1

Anower . molar solublity of Pb Groy * In Pure water .Pb Goyano s Pb2M + Gyomon S s Solublity product sp= (P621] [crouto] 2.8x10-13 = S = 5.29 x 100 M Solublity = molar solublity amolar mass of Plot Oy = 5.2.9 x1007 med x 3 23.1936 B/mol Solubliny - 1.71 x 10-48 © In 0.0060 M Max Co Oy Nazorou - anat + 60% 240.006oM 0.6060M It gives 0.0060M Pb Gay - croit initially P621 + s Goula 0.0060+ s)

Ksp = [P621] [crout] 218 810-13 = s (0.0060+5) since Kop is very low sach 0.0060 2.8 X 1013 S X 0.0060 s = 4.67 x 10-11 my Solublity = 4067x10-11 MX 323.1936 g/mol Solublity = 1.51 x 10-3 911 I