Question

A static pressure gauge and mercury manometer are connected to a 50.8 cm diameter pipeline Blowing full of water. One cubic centimeter of mercury has a weight of 0.1336 N. What is most neatly the velocity at the center of the pipeline? 10342 Pa 60.96 cm flow ---- 50.8 cm 50.8 cm 25.4 cm water mercury (A) 0.66 m (B) 0.19 m (C) 45 (D)

Answer 1

10342 - 160.96 cm 11 50.0 Sw=103 kg/m3 cm g=9,81 m/s2 h Manometer at A is set in the direction of flow so, it will give the sum of pressure head and kinetic head cat point A. PA+ 2 -PV² = Manometric pr. = at A -CU To get manometric pressure Use manometric ear at A. (Manometric pressure + Sw gx(0.762) -011336. (%) n (01254) = 0 (Manometric pressure) = 26459. LQ Pa

Now compute pressure at A PA= 10342+ Swxgx0,6096 PA = 16322:176 Pa] Now, from equ li Substituere value of PA A Manome tric pressure . 16322.576 +CM = 26453.18 {x10*V = 40137 TVA= 4.50 mls option (C) is correct.

In all calculation I used only SI units

Density of water=1000kg/m^3

Acceleration due to gravity =g=9.81m/s^2

When manometer is placed in the direction of flow it creates stagnation point at A and because of that the manometer gives pressure equals to both pressure head and velocity head.

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Thank you