Question

How can I modify my program to return the option with the highest amount ?

//A new author is in the process of negotiating a contract for a new romance novel.

//The publisher is offering three options.

//1. The author is paid $5,000 upon delivery of the final manuscript and $20,000 when the novel is published.

//2. In the second option, the author is paid 12.5% of the net price of the novel for each copy of the novel sold.

//3.In the third option, the author is paid 10% of the net price for the first 4000 copies sold, and 14% of the net price for the copies sold over 4000.

//The author has some idea about the number of copies that will be sold and would like to have an estimate of the royalties generated under each option.

//Write a program that prompts the author to enter the net price of each copy of the novel and the estimated number of copies that will be sold.

//The program then outputs the royalties under each option and the best option the author could choose. (Use appropriate named constants to store the special values such as royalties rates and fixed royalties.)

#include<iostream>

#include<iomanip>

using namespace std;

class author {

public:

void getData();

void printData();

int option_1();

int option_2();

int option_3();

private:

bool isFound = false;

double netprice;

int copies;

int option;

};

int main () {

author Twain;

  

Twain.getData();

Twain.printData();

return 0;

}

void author::getData() {

cout << "Enter the net price of each copy of the novel: ";

cin >> netprice;

cin.ignore(100, '\n');

cout << "Enter the number of copies that will be sold: ";

cin >> copies;

cout << endl; }

int author::option_1() {

return 5000 + 20000; }

int author::option_2() {

return (netprice + (netprice*.125)) * copies ; }

int author::option_3() {

if (copies < 4000)

return (netprice + (netprice*.10)) * copies;

else

return ((netprice + (netprice*.10)) * copies) + ((netprice + (netprice*.14)) * copies); }

void author::printData() {

cout << left << setw(20) << "Net Price: " << netprice << endl;

cout << left << setw(20) << "Copies: " << copies << endl;

cout << left << setw(30) << "\nAmount for each option: " << endl;

cout << left << setw(20) << "Option 1: " << option_1() << endl;

cout << left << setw(20) << "Option 2: " << option_2() << endl;

cout << left << setw(20) << "Option 3: " << option_3() << endl; }

Answer 1

If you have any doubts, please give me comment...

#include<iostream>

#include<iomanip>

using namespace std;

class author {

public:

void getData();

void printData();

int option_1();

int option_2();

int option_3();

int highest();

private:

bool isFound = false;

double netprice;

int copies;

int option;

};

int main () {

author Twain;

Twain.getData();

Twain.printData();

return 0;

}

void author::getData() {

cout << "Enter the net price of each copy of the novel: ";

cin >> netprice;

cin.ignore(100, '\n');

cout << "Enter the number of copies that will be sold: ";

cin >> copies;

cout << endl;

}

int author::option_1() {

return 5000 + 20000;

}

int author::option_2() {

return (netprice + (netprice*.125)) * copies ;

}

int author::option_3() {

if (copies < 4000)

return (netprice + (netprice*.10)) * copies;

else

return ((netprice + (netprice*.10)) * copies) + ((netprice + (netprice*.14)) * copies);

}

int author::highest(){

int n1 = option_1(), n2 = option_2(), n3 = option_3();

if (n1>=n2)

{

if(n1>=n3)

return n1;

else

return n3;

}

else

{

if(n2>=n3)

return n2;

else

return n3;

}

}

void author::printData() {

cout << left << setw(20) << "Net Price: " << netprice << endl;

cout << left << setw(20) << "Copies: " << copies << endl;

cout << left << setw(30) << "\nAmount for each option: " << endl;

cout << left << setw(20) << "Option 1: " << option_1() << endl;

cout << left << setw(20) << "Option 2: " << option_2() << endl;

cout << left << setw(20) << "Option 3: " << option_3() << endl;

cout<<" Highest: "<<highest()<<endl;

}