Question

Part C - Calculate the load P required for a length change of 0.01 in A 6061-T6 aluminum tube is used as a sleeve for a steel post (Tool L2), as shown. When not loaded, and at a temperature of 60°F, both the tube and post have a length of 24 in The system is subjected to a load P and the temperature is increased to 115°F. Assume that both the tube and post are rigidly connected to the rigid cap. Determine the load P required to restrict the system's length change to an increase of 0.01 in. Material Modulus of elasticity, E (ksi) Coefficient of thermal expansion, a F-) 6061-T6, Aluminum 10.0 x 103 13.1 x 10-6 Tool L2, Steel Alloy 29.0 x 103 6.50 x 10-6 Cross section: rigid cap - Tool L2, Steel Alloy 6061-T6, Aluminum 1.25 Express your answer in pounds to three significant figures. Enter positive value if the force direction is the same as shown in the free-body diagram, and negative value if its direction is opposite.

Answer 1

1 steel ② Aluminium de s da 24" ME Ixi? = 0.785398 t2 = (1.5?- 1.25) = 0.53996. in 2 7 E, = 29x103 usi n = 10 x 103 kisi : a = 6.5x 100 lop i d =13-1x106 lor if allowed for free expansion, col, ole are. OT = 15F - 60F S SSF i free thermal expansions) on = id, oT = 24 x bisxio x 55 = 8:58 x 103 in ol = d₂oT = 24 x 13.0 x 106 x 55 = 17.292x103 in 0.01. in 210 x103 in axial deformations ..si - ok-ody - (10- 8.58% 103 di = (1.42x103) in Seoh-olz '5610 -19.262)/153 dz = (-7-292 x103) in olz .. . 19.292 I steel post . is in tension ; le tube is in compression 61-42x103) (0.785398) (29x403) A0288398) (29x403) = 1.347612 kip P = 8,4,, . LU

S Az Ez Pz - (-7-2022 y)2 (onstra)e company in - in = -1.640578 .: Efy = 0 = P +P, -1P21 = 0 AN PE (B) = P, (1.640578 - 1-347612) [p = 0.292966466 kip) IP21 P