Question

Write the output of the following function assuming it was called with the given function call a. Call: fun(4, 10); fo void fun (int a, int b) cout << b a << endl; if(a >= b) { 나 cout < "boo\n"; return; fun(a 1, b 1); cout << a << endl;

Answer 1

Output :

6
4
2
0
boo
-2
boo
-4
boo
-6
boo
-8
boo
-10
boo
-12
boo
-14
Indefinite loop

It is a recursive function and there is no base condition to stop the recursive call . So indefinite loop will execute.

void fun(int a,int b)
{
cout<<b-a<<endl;
if(a >= b)
{
  cout<<"boo\n";
}
fun(a+1,b-1); //recursive call
cout<<" "<<a<<endl;
}
int main() {
fun(4,10); //function call
return 0;
}