Question

Determine the capacity of a roll crusher. The separation is 7 mm, speed of the rollers is 50 rpm, roller diameter is 23 cm, roller length is 0.4 m, and material density is 2.9 g/cm3.

Answer 1

The capacity of the roller crusher is,

                     $Q=188.5DW\omega L\rho$

Here, D is the diamter of the roll, W is the width of the roll, $\omega$ is the speed in rpm, L is the distance between the rolls, and $\rho$ is the material density.

Substitute the numerical values in the above equation and solve for capacity of the roller.

                 $Q=188.5(0.23 \mathrm{m})(0.4 \mathrm{m})(50 \mathrm{rpm}) (0.007 \mathrm{m})(2900 \mathrm{kg/m^{3}})$

                  $Q=17602.13$ t/m³