Question

2. In the figure to the right, a non-conducting, uniformly charged, straight rod has a charge of Q-8.40 nC and a length of L-12.0 cm. جانب a) Show that the electric potential due to the rod is given by: V = kain (+2+y where y is the vertical distance from the end of the rod, L is the length of the rod and is the rod's charge density. (9 pts) b) If a proton starts from rest at P1, find its speed very far from the rod. (9 pts)

Answer 1

andat D D --- — consider a small length element - dx at a distance a from the end. charge on da a nda. potential at P, due to this element dan dv= K. è da .. O dva kilometer - [m3 dite] IKE - Atto Total potential at P, due to whole rod-. *k/log (x + V2=72)] la log (ar Vazar) = Ak [ 10g (++ V2+94) – 1099] v ak log [typist] b) A4 a very good as the proton moves away from Pi, the Kinetic energy of it increases and potential energy decreases. So, if at a rosso far point(y) if he is the relocity of the proton, then // mp rez= er Imp a proton mass 7 le e proton change MP 2edk NLP+ y2 JL -yi ne [ zev ]'? je s 2008 109 [L*\r]] if 43XL, die very far point prese ...Ws szerinte log (it 3] ver 10g (+ -)