Question

The reaction: NO2(8) ---> NO(g) + 1/2O2(e) is second order and it takes 46 seconds for the [NO2] to go from 0.04 M to 0.02 M. How long will it take for the [NO2) to go from 0.02 M to 0.01 M? 92 seconds 138 seconds 46 seconds 184 seconds

Answer 1

For the reaction NO2(9) —> NO (9) + [ 02 (9) 34 is a second ander reaction. go from &= 468 required for the [NO₂] to 0.04.M to 0:02M so, [No, Jinitial = [N023470 = 0.04M and [NO, Ze= 468 = 0.02 M The integrated equation for and order reaction is. kt - shoe caso have k = + (dom - dom) = doo (som" – 25M-) 25M- 468 ka rate constant 0.543 8 ml

Let t = time required by [Nog] to go from 0.02M to o.olm Thus, 1o.orm 0.02 M oste milot (100m." – 50 m') = 50 0.543 MT st 4 = 92-18 = 4,2 :9287 Thus to go from [NO2] will take 928 0.02M to 0.01 M. Corred ophion : @