Question

2. Find the variables Bus, Bus, Sic and so in terms of 12. Write loop closure equations and the position analysis steps cleary. [55 MARKS] AB=r2 AD= 1 AQ=b1 BC=r3 EC-rs ht

Answer 1

data from the given question Link DB are leads The horizontal and vertical components of written and are equated to the respective lengths and components from AB, This us to two equations from which 013 and 543 can be calculated. * The horizontal and vertical DC are equated to respective given tengths and the components of EC which again which 015 components of link deads us to two and s16 can be calculated equations from * are LOOP closure equations written in the end in the rector format, The addition of two vetors resulting in a third rector. AY -> 0,3 012 4 5 Q. A 516 015 ܥܓܛ

LABL=hz 2 TADI:hi IAQI = bi IBC1:23 ledl=ht » AB) SIN 012= (DB) sin 013 h2 sin 02 - (DB) Sin 013 82 sin 012 = Suz sin 0,3 -O (DB) COS 013 (OA) + (ABIC03012 343 C08013= 4thcoso 120 → EC sin 015 = 316 +(00) Sin 013 (3) os sin 0,5- 316+(843703) sin 013 egno leq" @ 82sin 012 Tan 013² 8,782003012 0133 T Taño 02 sin 012 resino 31702 COSOR 543² sinstañ ( oz sino 12 5,4 ore) } 8,482003012 DC COS 013 - DA+ AQ + EC COS 0,5- 1843 +03) C03013= gitbit og COS 015 203015 - (1 Su3 +03) C08013-7,-61) 85 82 Sin 012 +83 frems vai Tañ / Dzsingiz } 3,732603012 C03015 - sin (tañ' (32sinos 0902)} 317d2CO3O2 8,-bi] 85

from ean 325002 +33 } sin 2012)} 316 = =89 Sin 0,5 – sinstañ! (özsing2 dito,cosa { Tañol desin 012 87&COSO Ois is evaluated above ) } ECE DAT AB= DB DC+cDG AB + BC = AETEZ