In a titration, a student found that 42.6 mL of a KOH solution were required to neurtralize 28.9 mL of a 0.160 M sulfuric acid solution. Determine the molarity of the KOH solution. SHOW WORK.
2KOH(aq) + H2SO4(aq) ------> K2SO4(aq) + 2H2O(l)
Balanced chemical equation is:
1 H2SO4 + 2 KOH ---> 1 K2SO4 + 2 H2O
According to balanced reaction:
2*number of mol of H2SO4 =1*number of mol of KOH
2*M(H2SO4)*V(H2SO4) =1*M(KOH)*V(KOH)
2*0.16*28.9 = 1*M(KOH)*42.6
M(KOH) = 0.217M
Answer: 0.217 M
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