Question
state the equation that you use

Semiconductor Germanium has a density of 5323 a. cm- and atomic mass of 72.63u. If we assume that Germanium can contribute 1
E1, frd = eftew+1E2, ~êr = ()**; Superconductor E3, M05T, = constant; E4, E,0) = 3.54k87c; E5, E,(T) = 1.74E,(0)(1-3)*; E6, c
E19 Nuclear decay: N(t) = N, e-t, N, number of isotope at t=0, N(t) number of isotope at time t; half-life, t1/2 = 0.393 E20,
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Answer #1

Sol? density s=5323 gm / cm3 Volume = 2x10x10=200cms mass of sample mz vxS = 200 x 5323 gm m = 1067.6 kg 14 = 1.66810-27 kg 7For query do comment. Thank you. Like Please

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