Here, we have given that
n= number of campers =74
= mean
starting BMI = 34.4
=mean ending
BMI= 30.7
S1= starting BMI standard deviation = 7.1
S2= ending BMI standard deviation = 6.4
= Mean
difference= 3.7
S.D(diff) =standard deviation of difference = 1.5
Claim: To check whether the mean BMI at the end of camp is less than the mean BMI at the end of camp.
The Hypothesis is
Ho: \mu d= 0
v/s
H1: \mu d < 0
Here, we use paired difference t test because the assumptions of independent sample is invalid
and data is in pre and post format.
Now,
Now, we can find the test statistic


=21.22
we get test statistic is 21.22
the test statistics using the formula for paired difference t-test
Degrees of freedom = n-1= 74-1=73
= level of
significance=0.01
Now, we can find the P-value
P-value = 0.0000 ( using EXCEL =TDIST(x,D.F,tail=1))
Decision:
P-value < 0.01 (
)
Conclusion:
That is we fail to reject Ho (Null Hypothesis) because P-value
< 0.01 (
)
There is not sufficient evidence that the mean BMI at the end of camp is less than the mean BMI at the end of camp.
9. option A is correct that Yes , in order to make the valid
small sample inferences about
the differences
need to be normally distributed.
(B)
Now,
Formula for CI is as follows

First we find the critical value
Degrees of freedom = n-1 = 74-1 = 73
= level of
significance=0.01
We get
Tc= 2.645 ( using t table)
Now,



Interpretation:
This confidence interval shows that we are 99% confident that the difference in the population mean will falls under this interval.
ot camp. Summary statistics on BMI maasuraments are shown in thetabla to tha right Camplato partsathrough...
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