Question

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Data Concentration of the Na S.O, solution: 0.0500 M Part I. Molar Solubility in pure water Data Trial 1 Trial 2 Volume saturated Ca(10), titrated, mL 10.00 10.00 Final buret reading, mL (Sin becomes colorless.) 28.15 27.50 Initial buret reading, mL 0.00 0.00 Volume delivered, mL AV = V-V Part II. Molar Solubility in 0.0100 M KIO, Data Trial 2 Trial 1 10.00 10.00 Volume Ca(10), in KIO, titrated, mL 40.45 39.95 Final buret reading, mL (Sin becomes colorless.) 0.00 0.00 Initial buret reading, mL Volume delivered, mL AV = V-V.

Answer 1

CA ② Molar Solubility of Ca (103) 2 u Pure water n = I x avouage conc. of (103] Ź x 0.0230M = 0.0115 M (3 Ksp solubility constant) for Ca(103), in Pure water. Ca (10₂) Ca 2+ + 2202 s Ksp = 5 (25) 2 2) 453 Kse Solubility Constant) = 4x (0.0115) - 6.08 x 10-6

Answeri The Reaction happens on that place, I o² + 5 It GHT 3 I2 + 3H₂02 6S20² + 3 I, - 6I +3540 1 mol. Iož - 6mol. S₂02 2- [Na₂S₂O3] = 0.0500m. as above Shows volume will be Trial i volume delivered a 28015 Trial 2. 27.50 6 momol of S. Or used (280 158 0.05) (27.50 x0.05) mmol of Ioj titrated (28. 15x0.05) (27050X0005) concentration of (28. 1580.05 -0.023M = 0·0229m 1 027 ium verage (1 03 / 0.0 23 06 0.0 229) m = 0.0230M 6810

Trial I Trail 2 ③ mmel e S2O3 used = 40.45X0.05 39.95 X0.05 mmol of 10 titrated = (400 4500.05) 139095X0.05) concentration of (10₂] = (400 45 x 0.05). (39.95 x 0.05) 6x10 6x10 = 0.0337 M = 0.0332 M Average of concentration & (0.0337 + 0.0332) or [103] 2. 2 0.0669 ) 0.0335 m 2 16 Total [10₂] = 0.0335 m -[103] from kl 0g = 0.0100m LI 03- .foom di'isolved Ca(10312 = (0.0335-000100) = 1000235 m) (6 Molau solubility of Ca(103)₂ in 0.0loom KLO₂ = I x000235 - 0.0118 M

Concentration of the Na S.O, solution: 0.0500 M Part I. Molar Solubility in pure water Data Triall Trial 2 Volume saturated Ca(10), titrated, mL 10.00 10.00 Final buret reading, ml (Sin becomes colorless.) 28.15 27.50 Initial buret reading, ml 0.00 0.00 Volume delivered, mL AV = V-V. 28.15-0.00=28.15 27.50-0.00=27.50

Part II. Molar Solubility in 0.0100 M KIO Data Trial 1 Trial 2 10.00 10.00 Volume Ca(10), in KIO titrated, mL 40.45 39.95 Final buret reading, ml (Sin becomes colorless.) 0.00 0.00 Initial buret reading, ml 40.45-0.00=40.45 39.95-0.00=39.95 Volume delivered, ml AV=V-V

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