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The scheduling graph represented below has tasks that can be completed in 1 unit of time. A / 0- 6 Find the following: 1) The
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Answer #1

1) The least amount of time to complete all tasks = 0 + 1 + 1 + 2 + 2 + 3 = 9

2) The latest time that E can start = 4 (when the path is A -> B -> C -> D -> E)

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