Dinitrogen pentoxide (N2O5) decomposes in chloroform as a solvent to yield NO2 and O2. The decomposition is first order with a rate constant at 45 ∘C of 1.0×10−5s−1.
Calculate the partial pressure of O2 produced from 1.20 L of 0.681 M N2O5 solution at 45 ∘C over a period of 18.6 h if the gas is collected in a 11.6-L container. (Assume that the products do not dissolve in chloroform.)








Partial pressure of oxygen = 0.449 atm
Dinitrogen pentoxide (N2O5) decomposes in chloroform as a solvent to yield NO2 and O2. The decomposition...
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10-3min-1. If a rigid vessel initially contains only N2O5 at a pressure of 125 kPa, how long will it take for the total pressure to reach 182 kPa?
The gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g) 2 NO2(g) + ½ O2(g) is first order in N2O5 with a rate constant of 4.70×10-3 s-1. If the initial concentration of N2O5 is 4.50×10-2 M, the concentration of N2O5 will be ______ M after 259 s have passed.
The decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C N2O5 -----> 2 NO2 + ½ O2 is first order in N2O5 with a rate constant of 4.10×10-3min-1. If the initial concentration of N2O5 is 1.45 M, the concentration of N2O5 will be_______ M after 337 min have passed.
Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitrogen pentoxide and has a half-life of 2.81 h at 25 ?C . If a 1.7-L reaction vessel initially contains 760 torr of N2O5 at 25 ?C , what partial pressure of O2 is present in the vessel after 205 minutes?
Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitrogen pentoxide and has a half-life of 2.81 h at 25 ∘C If a 1.4 L reaction vessel initially contains 760 Torr of N2O5 at 25 ∘C, what partial pressure of O2 will be present in the vessel after 230 minutes?
1A. The decomposition of dinitrogen pentoxide in carbon
tetrachloride solution at 30 °C N2O5 2 NO2 + ½ O2 is first order in
N2O5 with a rate constant of 4.10×10-3 min-1. If the initial
concentration of N2O5 is 0.510 M, the concentration of N2O5 will be
M after 402 min h
1B. The gas phase decomposition of phosphine at 120 °C
PH3(g)1/4
P4(g) + 3/2 H2(g)
is first order in PH3
with a rate constant of 1.80×10-2
s-1.
If the...
For the gas phase decomposition of
dinitrogen pentoxide,
N2O52
NO2 + 1/2 O2
the rate constant at 320 K is
6.13×10-4 /s and the rate constant at
355 K is 2.79×10-2
/s.
The activation energy for the gas phase
decomposition of dinitrogen pentoxide
is kJ.
The decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C N2O52 NO2 + ½ O2 is first order in N2O5 with a rate constant of 4.10×10-3 min-1. If the initial concentration of N2O5 is 0.444 M, the concentration of N2O5 will be 4.44×10-2 M after _________min have passed.
For the gas phase decomposition of dinitrogen pentoxide, N2O52 NO2 + 1/2 O2 the rate constant in s-1 has been determined at several temperatures. When ln k is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -1.24×104 K and a y-intercept of 31.3. The value of the rate constant for the gas phase decomposition of dinitrogen pentoxide at 322 K is_______ s-1.
For the decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C 2 N2O54 NO2 + O2 the average rate of disappearance of N2O5 over the time period from t = 0 min to t = 169 min is found to be 2.20×10-3 M min-1. The average rate of formation of O2 over the same time period is ______M min-1.