a)
Option B
b)
Probability of losing both games = (1-0.8)*(1-0.4) = 0.12
c)
probability of winning both games = 0.8*0.6 = 0.48
d)
P(X = 0) = 0.12
P(X = 1) = 0.8*0.4 + 0.2*0.4 = 0.4
P(X = 2) = 0.48
e)
E(X) = 0*0.12 + 1*0.4 + 2*0.48 = 1.36
Var(X) = (0 - 1.36)^2*0.12 + (1 - 1.36)^2*0.4 + (2 -
1.36)^2*0.48
= 0.4704
SD(X) = sqrt(0.4704) = 0.686
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