Question

fracture plane 3. An external fixation device is used to facilitate the healing of a fracture in the tibia. A force Fo applied at the foot causes the lower pin to rotate by an angle of 3° with respect to the upper pin. The rod has a radius of r = 4mm and is made of a material with shear modulus G = 60G Pa. Assume L = 300mm and L = 40mm. bone (a) . Calculate the value of the applied force Fo.

Answer 1

Fo=42N Sell The Answer is Explanation :- consider the device as a Cantilevere beam to k Uppere - pin Lire ...) 3º = read Lower Pin The expression fore end 6 = Fox(bre) 3 3x E XI deflection is t P E = modeles of Elasticity ſ = 2 G {essceme M=0} I = moment of inertia Fox (Lx 13 n re) = 120GPa . 3% E X64 TT = π d4 64 ST 3XTT?x120x10%(MPa)x64 - ? = Fo 60 x(340 mm)2 = 64 TT (mm) i fo = 42 N Anawer th