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1. Using the Epsilon Criterion on a function with one discontinuity Consider the function g : [0, 2] + R where g(1) = 5 and g

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Soli Given that consider function 9:[0, 2] =R whene 9(1) -5 and 962)= 1 otherwise, a) we know that → we find a partition p of+(91 P) = 1 (too-0) + (io-too)+--- +1(30 lente) • 2 (91P) = 200 100 NOW, we write 0(9,) - L (9,P) we can substinute given valwe consider, 30 (3,0) = 1000 - 0) + 1 (&poo - Loco) +... -t5 (soo - smag. J +3 (sobo - Go) + = 11998 6000 + s (Good) = 11998Now, we write U(9@) - L (9,2) we can substitute above values in given en [1998 10 - 12000 Good 6000 6000 = 12008-12000 6000 =we. M = Sup g(x) XE [1 / 11+ /2] m = inf 966) XE [1-3/211 +8/2] M-m 210 NOW, 39 is continuous on So, 1-3,) and [1+3,12] nNow, we consider given eqh U(P. 9)-1(P.9) - Su (p9)-1(210] + [u(Pag)- L(P29)] +(M-m) Le + & + los 4+ HOTE AU (P. 9) -L(Pag)e niven that -> Definition of Riemann integral we use, we know S?9 exists Now, we prove 529=2 Let us consider, $?9 exists co

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