What volume of 18.0 M sulfuric acid must be diluted to 250.0 mL to afford a...

Question

Question

Answer 1

Answer #1

Answer) This question can be solved by using,,

$\ M_{1}V_{1}= M_{2}V_{2}$

According to question,,

M1 = 18.0 M , V1 = _ mL , M2 = 0.55 M , V2 = 250.0 mL

So,

$\ 18.0*V_{1}= 0.55 *250.0$

$\ V_{1}= \frac{0.55 *250.0}{18}$

$\ V_{1}= \ 7.6\ mL$

Answer 2

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