Question

C++

Write a program with the following elements:

in main()

-opens the 2 files provided for input (Lab_HW9_2Merge1.txt and Lab_HW9_2Merge2.txt)

-calls a global function to determine how many lines are in each file

-creates 2 arrays of the proper size

-calls a global function to read the file and populate the array (call this function twice, once for each file/array)

-calls a global function to write out the 'merged' results of the 2 arrays

*if there are multiple entries for a person, these should be merged and should appear as a single entry in the resulting file

*resulting file should be named 'merged_output.txt'

program should check to see if a name is already present in one file or another. If the name is present in both files display the name once in the merged file and add the numbers.

Example:

1st File:

Carlos 7

Tina 3

2nd File:

Lena 2

Carlos 3

Merged File:

Carlos 10

Tina 3

Lena 2

Answer 1

#include<fstream> #include<iostream> #include<string> using namespace std; int lines (ifstream a) int c=0; while(!a.eof() c+=1; return c; int main() ifstream infilel, infile2; infilel.open("Lab HW9 2Mergel.txt"); infile2.open("Lab HW9 2Merge2.txt"); ofstream outfile; outfile.open("merged output.txt"); int fl=lines (infilel); int f2=lines (infile2); int x=0; string name1[fi], name2[f2], r[f1+f2]; int agel[fi], age2[f2], fa[fl+f2]; for(int i=0;i<f1;i++) infilel>>namel[i]; r[i]=namel[i]; //outfile<<name1[i]; infilel>>agel[i]; fa[i]=agel[i] //outfile<<agel[i]<<endl; 1

fa[i]=agel[i] //outfile<<agel[i]<<endl; for(i=0;i<f2;i++) infile2>>name2[i]; infile2>>age2[i]; for(int j=0; j<fl ; j++) { if(name2[i]==namel[j]) fa[j]=fa[j]+age2[i]; else r[f1+x)=name2[i]; fa[f1+x]=age2[i]; X=X+1; for(j=0; j<f1+x; j++) outfile<<r[j]; outfile<<fa[j]<<endl; infilel.close(); infile2.close(); outfile.close(); return 0;