1.
The time required for an automotive center to complete the service oil change service on an automobile approximately follows a normal distribution, with a mean 19 minutes and a standard deviation of 3 minutes.
a. The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take ionger, the customer will receive the service for half-price. What percent of customers recelve the service for half-price?
b. If the automotive center does not want to give the discount to more than 7 % of its customers, how long should it make the guaranteed time limit?
a. The percent of customers that receive the service for half-price is _______ %.
2.
The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day.
(a) Determine the 13 th percentile for incubation times.
(b) Determine the incubation times that make up the middle 39 %.
(a) The 13 th percentile for incubation times is _______ days.
The time required for an automotive center to complete the service oil change service on an automobile approximately follows a normal distribution
The time required for an automotive center to complete and change service on an automobile primately follows anomalion, with a man of 15 minutes and a standard deviation (a) The automotive center quanto customers that the service will take no longer than 20 minutes ir does take longer the customer will receive the service for all price. What percent of customers the si half price (1) of the automotive Center does not want to give the discount to more than...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard deviation of 2 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard deviation of 2 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 2.5 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want...
standard deviation of 1 day. The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with (a) Determine the 14th percentile for incubation times. (b) Determine the incubation times that make up the middle 39% of fertilized eggs. The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes standard deviation of 3 minutes. and (a)...
The time required for an automotive center to complete an oil change service on an automobile and a standard deviation of 2.5 minutes (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. Ifit does take longer, the customer will half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 3% of its customers, approximately kollows a normal distribution,...
4. [20 Points] The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard variance of 9 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center...
4. [20 Points] The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard variance of 9 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center...
4. [20 Points] The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard variance of 9 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center...
4. [20 Points) The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard variance of 9 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center...