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The 4 corners of a square of length L are located at (0,0),(a,0),(0,a),(a,a). There is a vector field E= 3ây. Denote by A the

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Answer #1

(6.a) , ca, as E by a) along path w Sed: 3y ² de = 1 yax a 2 (0.0 2 (0,0) since yao along as along (2): Edi = f by , dy g = 0

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