What is the mass per volume percent of a rubbing alcohol solution made with 331g of isopropyl alcohol in 473 mL of solution?

What is the mass per volume percent of a rubbing alcohol solution made with 331g of...
Rubbing alcohol is 70.% isopropyl alcohol by volume. How many mL of isopropyl alcohol are in 453 mLs?
Rubbing alcohol is a mixture of isopropyl alcohol (C3H7OH) and water that is 70% isopropyl by mass (D=0.79g/mL) Express the concentration of rubbing alcohol in molarity and molality
Rubbing alcohol is a solution of 70 percent alcohol and 30 percent water. In the alcohol solution, which is the solute and which is the solvent? Explain.
You have a solution which is 43.9% by mass isopropyl alcohol (MM = 60.11 g/mol) in water. The density of this solution is 0.905 g/mL. What is the molality of the isopropyl alcohol in the solution? What is the molarity of the isopropyl alcohol in the solution? What is the mole fraction of the isopropyl alcohol in the solution? What intermolecular forces are shared between isopropyl alcohol and water?
Calculate the volume percent of solute in each of the solutions. A solution made by adding 17.1 mL of methyl alcohol to enough water to give 489 mL of solution. % (v/v) = A solution made by adding 77.9 mL of ethylene glycol to enough water to give 213 mL of solution. % (v/v) =
1. A solution of rubbing alcohol is 76.5 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 77.5 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. 2. How many liters of a 3.18 M K2SO4 solution are needed to provide 98.8 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures.
1) A solution of rubbing alcohol is 69.0 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 88.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. 2) How many liters of a 3.06 M K2SO4 solution are needed to provide 83.8 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures.
29 You have a solution which is 43.4% by mass isopropyl alcohol (MM = 60.11 g/mol) in water. The density of this solution is 0.905 g/mL. a What is the molality of the isopropyl alcohol in the solution? > 1 point b What is the molarity of the isopropyl alcohol in the solution? > 1 point с What is the mole fraction of the isopropyl alcohol in the solution? > 1 point
You have a solution which is 43.4% by mass isopropyl alcohol (MM = 60.11 g/mol) in water. The density of this solution is 0.905 g/mL. What is the molality of the isopropyl alcohol in the solution?
29 You have a solution which is 43.4% by mass isopropyl alcohol (MM = 60.11 g/mol) in water. The density of this solution is 0.905 g/mL. b What is the molarity of the isopropyl alcohol in the solution? > 1 point с What is the mole fraction of the isopropyl alcohol in the solution? 1 point d What intermolecular forces are shared between isopropyl alcohol and water? 1 point