find the area of the shaded region
SOLUTION :
f(x) = √x and g(x) = 3/2 - x/2
Point of intersection :
f(x) = g(x)
=> √x = 3/2 - x/2
=> 2√x = 3 - x
Squaring
=> 4x = 9 - 6x + x^2
=> x^2 - 10x + 9 = 0
=> (x - 1)(x - 9) = 0
=> x = 1, 9
X = 9 is irrelevant here,
So, x = 1 .
As per given figure :
Shaded Area
1 3
= ∫ f(x) dx. + ∫ g(x) dx
0 1
1 3
= ∫ x^(1/2) dx + ∫ (3/2 - x/2) dx
0 1
1 3
= [2/3 x^(3/2)] + [3/2 x - x^2/4}
0 1
= 2/3 + [(3/2 (3) - 3^2 /4) - (3/2 (1) - 1^2/4)]
= 2/3 + [9/4 - 5/4]
= 2/3 + 1
= 5/3 ( ANSWER).
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00 3 attempts left Check my work Find the area of the shaded region where f(x) = cos(x). 6.66 points eBook !!! Print References COSY