Question

use python

2a. Union (1 points) Make a union function which takes in 2 lists as parameters and returns a list. It should return a list that contain all elements that are in either list. Your results list should contain no duplicates. For example, if the two lists are [1,5,6,5, 2] and [3,5, 1,9] then the result list is (1,5,6,2,3,9). Note that the list sizes don't have to be equal. Note that the input lists could have duplicates, but your resulting list should not. The order of the elements in the result list is not important. Also, neither list passed in should be modified. You should probably check this last point by printing out one of the original lists after the call. That is, something like: a = [1,2] b = [2,3,4] print(union(a,b)) # should print (1,2,3,4] print(a) #a should be [1,2] print(b)#b should b [2,3,4] 2b. Intersection (1 points) The other function you should write is intersection. Everything described above applies here as well, only this function should return a list that contains only the elements that are in both lists (no duplicates). So for the a and b above: print(intersection(a,b)) #should print [2] Note: do not use Python Sets to do this - this problem is for you to practice using list. Again, the lists passed in should not be modified. You should probably check this last point by printing out one of the original lists after the call. That is, something like:

Answer 1

Python code:

#defining union function
def union(list1,list2):
    #initializing a new_list
    new_list=[]
    #assigning all elements in list1 to new_list
    new_list+=list1
    #looping through all elements in list2
    for i in list2:
        #checking if that element is not in list1
        if i not in list1:
            #adding that element to new_list
            new_list.append(i)
    #returning new_list
    return new_list
#initializing list a
a=[1,2]
#initializing list b
b=[2,3,4]
#printing their union
print(union(a,b))
#printing list a
print(a)
#printing list b
print(b)

#defining intersection function
def intersection(list1,list2):
    #initializing a new_list
    new_list=[]
    #looping through all elements in list2
    for i in list2:
        #checking if that element is in list1
        if i in list1:
            #adding that element to new_list
            new_list.append(i)
    #returning new_list
    return new_list
#initializing list a
a=[1,2]
#initializing list b
b=[2,3,4]
#printing their intersection
print(intersection(a,b))
#printing list a
print(a)
#printing list b
print(b)

Screenshot:

1 #defining union function 2. def union(listi,list2): 3 #initializing a new_list 4 new_list=[] 5 #assigning all elements in listi to new_list 6 new_list+=listi 7 #Looping through all elements in list2 8. for i in list2: 9 #checking if that element is not in listi 10 if i not in listi: 11 #adding that element to new_list 12 new_list.append(i) 13 #returning new_list 14 return new_list 15 #initializing list a 16 a= [1,2] 17 #initializing list b 18 b=[2,3,4] 19 #printing their union 20 print(union(a,b)) 21 #printing list a 22 print(a) 23 #printing list b 24 print(b) 25 26 #defining intersection function 27. def intersection(listi, list2): 28 #initializing a new_list new_list=[] 30 #Looping through all elements in list2 31 - for i in list2: 32 #checking if that element is in listi 33 if i in listi: 34 #adding that element to new_list 35 new_list.append(i) 36 #returning new_list 37 return new_list 29 mm mm

Output:

38 #initializing list a 39 a=[1,2] 40 #initializing list b 41 b=[2,3,4] 42 #printing their intersection 43 print(intersection(a,b)) 44 #printing list a 45 print(a) 46 #printing list b 47 print(b)

[1,2,3,4] [1,2] [2,3,4] [2] [1, 2] [2,3,4]