Question

(1 point) R. x (t) The fundamental frequency of the input signal is Passives Value lk 2.5 μν 0.45 μ V 0.6 μν 1.75 kS2 -0.5 μ V -0.4 μ ν 1 What is the time-domain function for the output voltage? (Phase shifts should be in radians)

Please take into consideration the Fourier coefficients

Answer 1

a_0 = 2.5 mu V for dc equivalent ckt is for fundamental frequency phase of V_0 = tan^-1(1/w R_c) Lead = tan^-1(1/590 times 1.75 times 10^3 times 1 times 10^-6) = 44 degree C_1 = squareroot a^2_1 + b^2_1 = 0.672 mu V theta = tan^-1(b_1/a_1) = -48 degree Z_1 = squareroot R^2 + (1/wc)^2 = 2.4362 gain = R/z_1 = 0.71832 \r\n o/p voltage for fundamental = 0.71832 times 0.6726 cos[590 t - 48 degree + 44 degree] = 0.4831 cos[590 t - 4 degree] mu V For second harmony phase of V_0 = tan^-1(1/2 w R_c) = 25.8391 degree (lead) C_2 = squareroot 0.6^2 + 0.4^2 = 0.7211 mu v theta_2 = tan^-1(b_2/a_2) = -33.69 degree z_2 = squareroot R^2 + (1/2 w R_c0^2 = 1.94437 gain = R/z_2 = 0.9 \r\n o/p voltage for second harmonic = 0.9 times 0.7211 cos[1180 t - 33.69 degree + 25 8391 degree] = 0.64899 cos[118.t - 7.85 degree] mu V