Question

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Question 22: (3 Points) A store delivery driver records the time (in minutes) it takes to deliver orders to homes in the community for six days. Those results are: 25, 22, 17, 20, 15, and 10. Assuming the population is normally distributed. Find the upper confidence limit of the 90% confidence interval for the average population delivery time. 21.59 18.24 13.81 25.89 None of the suggested answers are correct Question 23: The lower limit of a 95% confidence interval for the population proportion p given a sample size of 100 and sample proportion p=0.62 is equal to: (3 Points) 0.525 0.440 0.715 None of the suggested answers are correct 0.699 Question 24: (3 Points) If a sample of size 21 is selected, the value of A for the probability Plt 2 A) = 0.025 is: None of the suggested answers are correct 2.518 2.528 2.080 2.086

Answer 1

22).i am using minitab to solve the problem.

steps :-

copy the data in minitab and name the column x $\rightarrow$ stat $\rightarrow$ basic statistic $\rightarrow$ 1 sample t $\rightarrow$ select one or more samples each in a column $\rightarrow$ in the blank box below select X$\rightarrow$options $\rightarrow$ in confidence level type 90$\rightarrow$ in alternative hypothesis select mean $\neq$ hypothesized cake $\rightarrow$ ok$\rightarrow$ok.

the needed minitab output be:-

90% CI for μ

(13.77, 22.56)

none of the answers are correct

23).given data are:-

p= 0.62, n = 100, z* = 1.96

the 95% confidence interval be:-

$=\hat{p}\pm z^**\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

$=0.62\pm 1.96*\sqrt{\frac{0.62(1-0.62)}{10}}$

$\approx (0.525,0.715)$

the lower limit is = 0.525

24).sample size (n) = 21

df = (n-1) = (21-1) = 20

according to the problem:-

$P(t\geq A)=0.025$

$\Rightarrow P(t\leq A)=1-0.025=0.975$

$\Rightarrow A\approx 2.086$ [ in any blank cell of excel type =T.INV(0.975,20) ]

the value of A is = 2.086

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