
Practice Problems 1. Identify the monomers in the following polymers: laxmlht Heizelyt monomers monomers
When polymers are broken down into monomers, what would your body do with those monomers? Give two examples in the body.
2. Define metabolism. Provide an example of the following: use monomers and polymers for your answer. a. Anabolism b. Catabolism
Nucleic acid polymers are made of ______ monomers. What components make up this monomer? Be specific. Protein polymers are made of _______ monomers. What components make up this monomer? Be specific.
"Co-polymers" consist of two different monomers ("A" and "B") joined in an alternating fashion (ABABAB...). Block co-polymers also consist of two different monomers, but in this case blocks of polymer containing only A units are joined to blocks of polymer containing only B units (AAAAABBBBB...). How might block co-polymers be synthesized
12.56 What polymers are produced from the monomers: CH,-CHCN b. a.
1) Find two examples of other polymers that can be degraded into monomers). Provide chemical reactions. 2) Write any three organic reactions that the product (terephthalic acid) can engage in.
1-15 Which of the following monomers can conceivably form isotactic polymers? HH (a) CH2-C-C-CH, CH2 - CH2 (b) CH, Czo NH CH, - CH, CH, (c) CH3 - C=CH2 H H - C=CH, (d) CH - сн. (e) HOCHCH,OH + HO-C- 0-C-OH ? =0
you need to make a new linear, high molecular weight,
poly(amide) –
Give the structures of the polymers that could be formed from
the following monomers and in each case identify the repeating
unit.
Lecture 9 Activity: you need to make a new linear, high molecular weight, poly(amide) Give the structures of the polymers that could be formed fromm the following monomers and in each case identify the repeating unit. - 1.H2N NH2C CI он OH HO Cl Cl
Lecture...
Starch polymers are broken down by enzymes into monomers called: a.)maltose b.) dextrins c.) glucose d.) sucrose
2. How many stereoregular polymers might possibly be obtained from each of the monomers? Explain your answers (6 pt) a) CH2=CH-CH3 b) CH2=C(CH3)-CH=CH2 c) HO-(CH2)6-OH + HO2C-(CH2)4-CO2H