Question

please answer question # 5

6. A charge of -27 HC is distributed uniformly throughout a spherical volume of radis 13.0 cm Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Hint: you need to determine the radial component of the electric field.) (a) 4.0 cm (b) 10.0 cnm (c) 26.0 cm 7. A charge of -20 C is distributed uiformly over the surface of a spherica conductor of radius 11.0 cm. Determine the electric field i N/C) due to this charge at the following distances from the center of the sphere. (Hint: you need to determine the radial component of the electric field.) (a) 7.0 cm (b) 8.0 cm (c) 24.0 cm 8. A long silver rod of radius 6 cm has a charge of-6C on its surface (a) Find the electric field (in N/C in the f direction) at a point 14cm from the center of the rod (an outside point) (b) Find the electric field (in N/C in the f direction) at a point 1 cm from the center of the rod (an inside point) 9 Two parallel plates 13 cm on a side are given equal and opposite charges of magnitude 9.0 × 10-9 C. The plates are 1.7 mm apart. What is the magnitude of the electric field (in N/C) at the center of the region between the plates?

Answer 1

question #5 is not given so we solve #6

Radius of the sphere is R = 13 cm = 0. 13 m charge of the sphere is Q = -27 mu c = -27 times 10^-6 c volume charge density of the sphere is row = Q/4/3 pi R^3 we draw a Gaussian surface of radius r = 4 cm = 0. 04 m concentric with the sphere total charge in closed by the Gaussian surface is Q_in = row times volume of the Gaussian surfaces q_in = Q/4/3 pi R^3 times 4/3 pi r^3 q_in = Q r^3/R^3 now from gauss's law integral E^rightarrow A^rightarrow = q_in/epsilon_0 E. 4 pi r^2 = Q r^3/R^3 epsilon_0 E = Q r/4 pi epsilon_0 R^3 E = 9 times 10^9 times 27 times 10^-6 times 0. 04/0. 13)^3 since 1/4 pi epsilon_0 = 9 times 10^9 \r\n E = 4. 424 times 10^6 v/m