Question

A 50.0 mL solution of 0.146 M KOH is titrated with 0.292 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl. 0.00 mL pH = 6.00 mL pH = 12.5 mL pH = 1 20.0 mL pH = 24.0 mL pH = 25.0 mL pH= 26.0 mL pH = 29.0 mL pH =

Answer 1

Concentrateen of KOH=0:146.14 = 0,146 mol/L Volume of KOLOSolution = 50c0ml = 50mm = 0.05L Nenubes neoles of KOH = 0.146 hol/LX0OSL = 0.0073 mol Concentraleem of Hel = 0-292M=0-292 90112 Volume of bel Solutien added = 0.00ml Sêne Kolt is a strong base falace it disocietes I completely into ions these fore, Toho kout = 0.146 MB IPOH = -lolo 7 =-1090.146=-(-0-836) = 0-836 | PH = 14.00POH = 14.00-0-836 = 13.16 L PH = 13.16 De X I volume of Hel solution added = 6.00ml = 6.00€ 0.006L Ausubes of roles of Hel = 0.0064 x 0.292 meliz = 0.001752mol Reactérie Hel (292+ KOH1027 Kelas+H206 From reactien 1.0 mol of Hel reacte weelta 1.0 mol of kot then 0.001752 mol of Hel will reach-coell 10000175 2 nal of Konto Nesuber of nooled of koh remercênêng = (0.0073-0.001752) v=0.095548 mol Total volume of schulēm = (0,006+0.05)L=0.066k Senelerle, cou_7[-0.0053 48 nol 20.09907nell IC 0.056L

A zmol/LX0.01281=0.0036 nal 0.06251 L POH = -loq 0.0 9907 = -(-4:00) = 1:00 LPH = 14.07- .00 = 13.00 P H = 13:00 - Ann Volume of Hel Solute an Added = 12.5ml = 1000 Ninutes of redes Of Hel = 0.292 molllxo.0125L=0.00 Sêncelasly 0.00385 moles of Hel ciell react welk o.0036Śwel of Kohto Nerebes of medles of kol renaining = (0.0073 -0.00365)mel = 0.00365 mol Total Voletome of solulêm= (0.05+0.0125) L = 0.06252 Similarly OHR=[[301]= 0.0034£ mal = 0.0584 molt 2 POH = -log[0] = -log 0.0584 =-(-1.23)=1.23 PH = 14.00- 1.23= 12.77 PH= 12.77-en I volume of Hel Scheffen added = 20.0ml=20.04=0.024 Neneker ofhuoles Ofeltet = 0.292nal/1.X0-024 = 0.00584 mol Senålares, O.OOSB4 hrool of Hel will react wêlth O. ODSBY : mol of koto Neubes of mobles of koh remaining = (0.0043-O.CO88) I= 0.00146 mol Total volume of solution = (0.02+0.05)L = 0.07 L Semnelosky 1047=K01])= 0.00146 mol 0.02086 bolell

POH = -loq 0.02086 = -(-1.60) = 1.68 PH = 14.00-1068 = 12.32 PH = 12.324 seammeet CamScanner