Question

R S2 Sy R: с 6. A capacitor, three batteries, three resistors, and three switches (S1, S2 and S3) creates the left side circuit. Values of circuit elements are given as C= 20 pF, 61= 2.0 V, Ez= 1.0 V, 5= 3.0 V, R=0.100, R2=0.050, and Rg=0.150. In the circuit established for a long time, S, and S, are open and S2 is closed. (a) Calculate the maximum charge on the capacitor using Kirchhoff's rules, if S, is then closed for a long time? (b) If suddenly S. and S2 are opened and S3 is closed, find the current that will pass through Rs depending on time. HH S; S HW Ri

Answer 1

Answer" when Sz is closed E3 R3 effective circuit and się S3 are open Sa E 3 R3 53 R, S2 H1 Rzi Ez HE Si + a a Capacitor in W RI effective change on charging ciscuit :- q=%. Co-est/RC) too At a long time C = 204F= 20x 10 q = 60 MC C effective acuit: qs9 CVE CEZ 20x106 E3=300v q=20x106x3 : 60x106 (6) S, and Se are open, and sz is closed this instant, the fully charged capacitor R3 acts a voltage source for gesistor R3 Ve+iR3=0 at iR 30 = a + da R3=0 rvet do 가 time to logq = -t tk av=90=Cv=CE;) 10990=0tk logq -log No = care >) 1096 ) -) V=Ve CR3 ir devedes) avoces) C At с c CR3 -t CR3 cassent is day -t есе at

is CR3 R3 la se) (-) negative represents decreasing in current is the cucuit ju V=CE₂ i eta e che -&R -> 11-1e e CR3 C=2047 Eze 3.0 V R3=0-15-2 -t 3 (20x106x0.15) 0.15 t li 20e 3x1606 А Answers Maximum charge Tro= 60x100c current through R3 Rz - i=-20 (106) A (3x 3Xю Hils 20 A